find p(0),p(-1),p(2) for the following case : p(x)=(x-1)(x+1)
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Given polynomial: p(x) = (x-1)(x+1)
To find:
i) p(0)
ii) p(-1)
iii) p(2)
Solution:
I) p(0) = (0-1)(0+1) = -1
ii) p(-1) = (-1-1)(-1+0) = 0
iii) p(2) = (2-1)(2+1) = 3
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