Question

Find p(0), p(1), p(–2) for the following polynomialp(y) = (y + 2) (y – 2).​

Answer 1

Answer:

P(y)=(y+2)(y-2)

P(0)=(0+2)(0-2)

P(0)=2×-2

P(0)=-4

P(y)=(y+2)(y-2)

P(1)=(1+2)(1-2)

P(1)=3×-1

P(1)=-3

P(y)=(y+2)(y-2)

P(-2)=(-2+2)(-2-2)

P(-2)=0×-4

P(-2)=0

Answer 2

I hope you have your answer dear and always be