Find p(0), p(1),p(-2) for the following polynomials.
i. p(x) = 10x - 4x2 - 3.
ii. p(y) = (y - 1)(y-2)(-3).
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Answered by
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Step-by-step explanation:
i) p(x)= 10x-4x²-3
=> p(0)= 10(0)-4(0)²-3
=0-0-3
= -3
=> p(1)= 10(1)-4(1)²-3
= 10-4-3
=3
=> p(-2)= 10(-2)-4(-2)²-3
=-20-16-3
= -39
ii) p(y)= (y-1)(y-2)(-3)
=> p(0)= (0-1)(0-2)(-3)
= -6
=> p(1)= (1-1)(1-2)(-3)
=0
=> p(-2)= (-2-1)(-2-2)(-3)
= (-3)(-4)(-3)
=-36
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