Question

find P(0),P(1), P(2) for the polynomial- 4x²+x-5​

Answer 1

Answer:

P(0)= -5 , P(1)= 0 , P(2)= 13

Step-by-step explanation:

Given that P(x) = 4x²+x-5

Let P(x) = P(0)

• P(0) = 4(0×0)+0-5
• =4(0)+0-5
• =0+0-5
• =-5

Let P(x) = P(1)

• P(1) = 4(1×1)+1-5
• =4(1)+1-5
• = 4+1-5
• = 5-5
• =0

Let P(x) = P(2)

• P(2) = 4(2×2)+2-5
• =4(4)+2-5
• =16+2-5
• = 18-5
• = 13

P(0) = -5 , P(1) = 0 , P(2) = 13