Question

find p(0) ,p(1) ,p(2) for the polynomial p(t)=2+t+2t-t²​

Answer 1

Step-by-step explanation:

p(0) =2+0+2x0-0²= 2+0=2

p(1)= 2+1+2x1-1²=2+2=4

p(2)= 2+2+2x2-2²=4

Answer 2

$\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>$

$p(t)=2+t+2t-t²$

$p(0)=2+0+2 \times 0-0² = 2$

$p(1)=2+1+2 \times 1-1² = 5 - 1 = 4$

$p(2)=2+2+2 \times 2-2² = 4 + 4 - 4 = 4$

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