Question

find p(0) ,p(1) ,p(2) for the polynomial p(t)=2+t+2t-t²​

Answer 1

Step-by-step explanation:

●Sol:-

p(0) = 2 + 0 + 2 × 0 - 0

= 2

p(1) = 2 +1 + 2×1 - 1

= 2 + 2 - 1

= 3

p(2) = 2 + 2 + 2 × 2 - 4

= 4 + 4 - 4

= 4

Answer 2

Answer:

Step-by-step explanation:

P(t)=2+t+2t-t²

So p(0)=2+0+0-0=2.

p(1)=2+1+2×1-1²

=2+1+2-1=4.

p(2)=2+2+2×2-2²

=2+2+4-4=4.