Question

find p(0),p(1),p(2) for the polynomial p(x)=(x-1)(x+1)​

Answer 1

Step-by-step explanation:

hope this is correct answer

Answer 2

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Answer:

p(0)-1 ,p(1)=0 ,p(2)=3

Step-by-step explanation:

Given:p(x)=(x-1)(x+1)​

To find:Values of p(x) at p(0),p(1),p(2)

Solution:Put x=0,1,2 in  p(x)=(x-1)(x+1)​:-

We get,

p(0)=(0-1)(0+1)=-1×1=-1

p(1)=(1-1)(1+1)=0×2=0

p(2)=(2-1)(2+1)=1×3=3

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