Question

Find p(0) p(1) p(2) in p(t)=2+t+2t^2-t^3

Answer 1

Answer:

p(t)=2+t+2t2-t3

p(0)=2+0+2*0*2-0*3

      =2

p(1)=2+1+2*1*2-1*3

      =4

p(2)=2+2+2*2*2-2*3

       =9

     

Answer 2

Answer:

p(0)= 2

p(1)=4

p(2)=4

hope it is helpful