Question

find p(0) p(1) p(2) p(-1) of the polynomials p(y)=2+y+2y-y​

Answer 1

Answer:

p(y) = 2 + y + 2y -y

the answer can simply be found by replacing y with tha given values.

so, p(0) = 2 + 0 + 2*0 - 0

= 2

p(1) = 2 + 1 + 2*1 - 1

= 2 + 1 + 2 - 1

= 4

p(2) = 2 + 2 + 2*2 - 2

= 2 + 2 + 4 - 2

= 6

p(-1) = 2 + (-1) + 2 * (-1) - (-1)

= 2 - 1 - 2 + 1

= 0