Question

find p(0), p(1),p(2),p(4) for each of the following p(y) =2+y+2y²​

Answer 1

Answer :

• p(0) = 2
• p(1) = 5
• p(2) = 12
• p(4) = 38

Step-by-step explanation :

Given polynomial,

p(y) = 2y² + y + 2

• p(0)

Substitute y = 0,

 => 2(0)² + 0 + 2

 => 2(0) + 2

 => 0 + 2

 => 2

⇒ p(0) = 2

• p(1)

Substitute y = 1,

=> 2(1)² + 1 + 2

=> 2(1) + 3

=> 2 + 3

=> 5

⇒ p(1) = 5

• p(2)

Substitute y = 2,

=> 2(2)² + 2 + 2

=> 2(4) + 4

=> 8 + 4

=> 12

⇒ p(2) = 12

• p(4)

Substitute y = 4,

=> 2(4)² + 4 + 2

=> 2(16) + 6

=> 32 + 6

=> 38

⇒ p(4) = 38