find p(0) ,p(1),p(2) when p(x)=x square -x +1
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Answered by
8
p(0) = 1
p(1) = 1
p(2) = 3
Hope it will help you ❤️
Answered by
0
Step-by-step explanation:
p(x) = x² - x + 1
p(0) = 0² -0 + 1 = 1
p(1) = 1² - 1 + 1 = 1
p(2) = 2² - 2 + 2 = 3.
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