Question

Find p(0) ,p(-2) for the polynomial p(y)=(y+2)(y-2)

Answer 1

Answer:

p(0)=4

p(-2)=0

Explanation:

p(y)=(y+2)(y-2)

p(0)=(0+2)(0-2)

=2×2

=4

p(-2)=(-2+2)(-2-2)

=(0)(-4)

=0

Answer 2

Answer:

So, p(0) is -4 and p(-2) is 0.

Thanks for question