Question

Find p(0), p(–2), for the polynomials

p(y) = (y + 2) (y – 2)​

Answer 1

Step-by-step explanation:

p(y) = (y+2) (y-2)

by using identity (a+b)(a-b) = a²-b²

=> p(y) = y²-(2)²

if p(0) then

p(0) = 0²- (2)²

=> p(0) = -4

if p(-2) then

p(-2) = 2²-(2)²

=> p(-2) = 0