Question

Find p (0),p(2), for the polynomials p(y) =(y+2) (y-2)​

Answer 1

Answer:

we have p(y)= (y+2) (y-2)

substituting y=0, 1and -2 respectively in (2) we get

p(0)= (0+2) (0-2)= -4

p(1)=(1+2) (1-2) = -3

and p(-2) = (-2+2) (-2-2) =0

hence the value of p(0) p(1) and

p (-2) are -4,-3 and 0

respectively

you are navodayan

class 9th

faizabad

मैं आप के class का हूँ