Find
p(0),
p(–2), for the polynomials
p(y) = (
y + 2) (
y – 2)
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0
Answer:
answer i donot know i am just doing it for points
Step-by-step explanation:
Answered by
1
Step by step
P(y) = (y+2)(y-2) = y^2 - 2^2
=y^2-4
Case 1 : p(0) = 0^2-4
= -4
Case 2: p(-2) = (-2)^2-4
= 4-4
= 0
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P(y) = (y+2)(y-2) = y^2 - 2^2
=y^2-4
Case 1 : p(0) = 0^2-4
= -4
Case 2: p(-2) = (-2)^2-4
= 4-4
= 0
Hope this helps
Mark me as the brainlist
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