Question

find p(0),p(2),p(-1) for p(y)=4y square-6y+7​

Answer 1

Step-by-step explanation:

Given there ,

1.p(y) = 4y square-6y + 7

p(0) = 4(0) square- 6(0) +7

=0-0+7

= 0 - 0

p(0) = 0

2.p(2) = 4(2) square- 6(2) + 7

= 4×2 square- 6×2 +7

= 8 square-12+ 7

= 16 - 19

p(2) = 3

3. p(-1) = 4(-1) square-6(-1) + 7

= -4 square- (-6)+ 7

= -16 +13

p(-1) = 9