Question

Find p(0),P(3) and P(-2) for the polynomial P(x) =5-4x +2x^2​

Answer 1

Step-by-step explanation:

p(0) = 5-4(0)+2(0)²

= 5-0-0

=0

p(3) = 5-4(3)+2(3)²

= 5-12+18

= 11

p(-2) = 5-4(-2)+2(-2)²

= 5+8+8

= 21

Answer 2

$\begin{gathered}\begin{gathered}{\huge{\textbf{\textsf{{\color{navy}{꧁An}}{\purple{sw}}{\pink{er꧂}}{}}}}} \\ \\ \end{gathered}\end{gathered}$

➜ when p(0)

• Put x = 0

$\pink\dashrightarrow$5 - 4x + 2x²

$\orange\dashrightarrow$5 - 4(0) + 2 × (0)²

$\blue\dashrightarrow$5 - 0 + 0

$\purple\dashrightarrow$5

➜ when p(3)

• Put x = 3

$\green\dashrightarrow$5 - 4x + 2x²

$\gray\dashrightarrow$5 - 4(3) + 2 × (3)²

$\pink\dashrightarrow$5 - 12 + 2 × 9

$\orange\dashrightarrow$5 - 12 + 18

$\blue\dashrightarrow$5 + 6

$\purple\dashrightarrow$11

➜ when p(-2)

• Put x = -2

$\gray\dashrightarrow$5 - 4x + 2x²

$\pink\dashrightarrow$5 - 4(-2) + 2(-2)²

$\orange\dashrightarrow$5 + 8 + 8

$\blue\dashrightarrow$21