Find p(0),p(3) of x³+x²+x+1
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0
Answer:
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Answered by
2
Step-by-step explanation:
p(x)=x³+x²x+1
p(0)=(0)³+(0)²+0+1
=0+0+0+1
=1
and,
p(3)=(3)³+(3)²+3+1
=27+9+4
=40
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