Question

Find P(1) & P (0) for P(y) = y2-y+1​

Answer 1

Step-by-step explanation:

Given, p(y) = y2-y+1

therefore, P(0)= 0^2 - 0 + 1

=1

and, P(1) = 1^2 - 1 + 1

= 1

Hope it helps