Math, asked by sunnynadala715, 1 year ago

find p(1)and p(2) of the polynomial
5y2-3y+7.​

Answers

Answered by decentdileep
3

p(y) \: 5{y}^{2}-3y+7 \\ p(1) = 5( {1})^{2} - 3(1) + 7 \\ p(1) = 5(1) - 3(1) +7 \\ p(1) = 5 - 3 + 7 \\ p(1 ) = 9 \\ p(2) = 5 ({2)}^{2} - 3(2) + 7 \\ p(2) = 5(4) - 3(2) + 7 \\ p(2) = 20  - 6 + 7 \\ p(2) = 21

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Answered by Anonymous
15

Solution :

Given:

  \star \:  \boxed{ \tt{ \red{p(y) = 5 {y}^{2}  - 3y + 7}}}

To Find:

  • p(1)
  • p(2)

Calculation:

  • p(1)

 \implies \sf \: p(1) = 5 {(1)}^{2}  - 3(1) + 7 \\  \\  \implies \sf \: p(1) = 5 - 3 + 7 \\  \\  \implies \:  \boxed{ \tt{ \blue{p(1) = 9}}}

  • p(2)

 \implies \sf \: p(2) = 5 {(2)}^{2}  - 3(2) + 7 \\  \\  \implies \sf \: p(2) = (5 \times 4) - 6 + 7 \\  \\  \implies \sf \: p(2) = 20 - 6 + 7 \\  \\  \implies \:  \boxed{ \tt{ \orange{p(2) = 21}}}

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