Question

find p (1) for polynomial y³+y²+1.
maths problem​

Answer 1

Given

➡ f(x) is a polynomial of degree 3 (cubic)

and p(x)=y³+y²+1

To find :

➡ p(1)=?

Solution:

$\\ \implies \large \sf \: p(x) = {y}^{3} + {y}^{2} + 1$

Put x=1 in the following equation to get p(1) values :

$\\ \implies \large \sf \: p(1) = {(1)}^{3} + {(1)}^{2} + 1$

$\\ \implies \large \sf \: p(1) = 1 + 1 + 1$

$\\ \implies \large \sf \: p(1) = 3$

➡ The value of p(1) is 3 which is our answer..

Answer 2

Answer:

3

Step-by-step explanation:

1^3+1^2+1

=3

hope it helps :)