Question

Find P-1, if it exist, given P =
=[1 -2
-5 10]​

Answer 1

Answer:

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Step-by-step explanation:

$\binom{1}{ - 5}\binom{ - 2}{10} \\ \\ \frac{1}{1 \times 10 - ( - 2) \times ( - 5)} \binom{10}{ 5} \binom{ 2}{1} \\ \\ \frac{1}{10 - 10} \binom{10}{ 5} \binom{ 2}{1} \\ \\ \frac{1}{0} \binom{10}{ 5} \binom{ 2}{1} \\ \\ the \: \: determinant \: \: is \: \: 0, \: \: matrix \: \: is \: \: not \: \: invertible.\\ \\ Hence, \: \: inverse\: \: of\: \: the \: \: matrix\: \: doesn't\: \: exists.$