Question

find p(1),if p(x) =x³-3x²+4​

Answer 1

Answer:

Step-by-step explanation:

1^3-3*1^2+4

1-3+4

2

Answer 2

$p(x) = x ^{3} - 3x ^{2} + 4$

So ,

$p(1) = 1 ^{3} - 3 \times (1) ^{2} + 4$

Then,

$p(1) = 1 - 3 + 4$

$p(1) = 1 + 1$

$p(1) = 2$

Answer

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