Question

Find p(1), p(0) and p(-2) for polynomial y^2 - 2y+ 5​

Answer 1

Answer:

Correct option is

A

2,4,4

Given polynomial is p(y)=2+y+2y

2

−y

3

Replace y by 0, we get

p(0)=2+(0)+2(0)

2

−(0)

3

⇒p(0)=2+0+0+0

⇒p(0)=2

Replace y by 1, we get

p(1)=2+1+2(1)

2

−(1)

3

⇒p(1)=2+1+2−1

⇒p(1)=4

Replace y by 2, we get

p(2)=2+2+2(2)

2

−(2)

3

⇒p(2)=2+2+8−8

⇒p(2)=4