Question

Find p(-1) + p(0) when p(x)=x^2-1

Answer 1

Answer:

Given value of x are (- 1) and 0

P(-1)= (-1)^2 - 1 =1-1=0

P(0)=(0)^2 - 1 =(-1)

P(-1) + P(0) = 0 + (-1) =(-1)