Question

Find p(1)- p(-1) for given polynomial p
P(t) = t 4- t3+ t2+6​

Answer 1

Answer:

Here's your answer.

Step-by-step explanation:

To find the value of p(1) - p(-1) first we have to find the values of both the p's

So, value of p(1) is :-

If p(t) = t4 -t3 +t2 +6 then,

p(1) = 1×4 -1×3 +1×2 +6

= 4 - 3 +2 +6

= 1 + 8

= 9

and ,value of p(-1) is :-

if p(t) = t4 - t3 + t2 +6

so, p(-1) = -1 × 4 + (-1 ×3) + (-1×2) +6

= -4 -3 -2 +6

= 2 - 5

= -3

Now , p(1) - p(-1) = 9 - ( -3)

= 9 + 3

= 12

Hence 12 is the final answer....

Hope it helps....pls mark me as the brainlisist.

Answer 2

Answer:

Solution: (i)p(y) = y2 – y + 1

Plug y = 0 we get

=>p(0) = (0)2 – 0 + 1

=>p(0) = 0 – 0 + 1

=> 1

Plug y = 1 we get

=>p(1) = (1)2 – 1 + 1

=>p(1) = 1 – 1 + 1

=> 1

Plug y = 2 we get

=>p(2) = (2)2 – 2 + 1

=>p(2) = 4 – 2 + 1

=> 3

Step-by-step explanation:

(ii) p(t) = 2 + t + 2t2 – t3

Plug t = 0 we get

=> p(t) = 2 + t + 2t2 – t3

=> p(0) = 2 + 0 +2(0)2 – (0)3

=> p(0) = 2 + 0 +0 – 0

=> p(0) = 2

p(t) = 2 + t + 2t2 – t3

Plug t = 1 we get

=> p(t) = 2 + t + 2t2 – t3

=> p(1) = 2 + 1 +2(1)2 – (1)3

=> p(1) = 2 + 1 + 2 – 1

=> p(1) = 4

p(t) = 2 + t + 2t2 – t3

Plug t = 2 we get

=> p(t) = 2 + t + 2t2 – t3

=> p(2) = 2 + 2 +2(2)2 – (2)3

=> p(2) = 2 + 2 + 8 – 8

=> p(2) = 4