find p(-1) when p(x)=x square-3x-4
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Answered by
2
p(-1)=(-1)^2 - 3(-1)-4
=1+3-4
=0
Therefore the value of p(-1) is 0
=1+3-4
=0
Therefore the value of p(-1) is 0
Answered by
1
Hyy
Here is the answer
x^2-3x-4
=(-1)^2-3x-1-4
=1+3-4
=0
Hope helped
Here is the answer
x^2-3x-4
=(-1)^2-3x-1-4
=1+3-4
=0
Hope helped
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