Question

Find p(10), p (20) and p(25) for each of the following polynomial (1) p. (x) =x²-x+1​

Answer 1

p(x)= x²-x+1

p(10) = 10²-10+1

= 100-10+1

= 91

p(20)= 20²-20+1

= 200-20+1

= 181

p(25)= 25²-25+1

= 625-25+1

= 601

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Answer 2

Answer:

put value of p =10

2

p(10)=(10)-10+1

= 100-10+1

= 90+1

= 91

put value of p =20

2

p(20) =(20) -20+1

= 400-20+1

= 380+1

= 381

put value of p= 25

2

p(25)= (25)-25+1

= 625-25+1

= 600+1

= 601

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