Question

find p (-2) if p (x) = 3-x- 2x²-x³​

Answer 1

Answer:

given p(-2) = 3-(-2) -2(-2)²-(-2) ³

=3+2-8+8

=5-0

=5

p(x) is 5

Answer 2

Step-by-step explanation:

p(x) = 3 - x - 2x² - x³

p(-2) = 3 -(-2) - 2×(-2)² - (-2)³

= 3 + 2 - 8 + 8

= 5 - 0

= 5

hence 5 is the zeros of polynomial of p(x)=3-x-2x²-x³

hope this helps you ^_^

(in exam conclusion sentence carries 1/2 or 1m) (in boards)

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