Question

Find p(-2) of the given polynomial . p(x)=10(x)-4(x)²-3
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Answer 1

Answer:

We have p(x)=10x−4x

We have p(x)=10x−4x 2

We have p(x)=10x−4x 2 −3

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0)

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1)

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1) 2

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1) 2 −3

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1) 2 −3∴p(1)=10−4−3=3

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1) 2 −3∴p(1)=10−4−3=3And,

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1) 2 −3∴p(1)=10−4−3=3And,p(−2)=10(−2)−4(−2)

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1) 2 −3∴p(1)=10−4−3=3And,p(−2)=10(−2)−4(−2) 2

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1) 2 −3∴p(1)=10−4−3=3And,p(−2)=10(−2)−4(−2) 2 −3

We have p(x)=10x−4x 2 −3∴p(0)=10(0)−4(0) 2 −3∴p(0)=0−0−3=−3p(1)=10(1)−4(1) 2 −3∴p(1)=10−4−3=3And,p(−2)=10(−2)−4(−2) 2 −3∴p(−2)=−20−4(4)−3=−20−16−3=−39

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