Question

find p(2),p(1) for this polynomial
p(y) = 2+y+2y^2-y^2​

Answer 1

Answer:

p(1) = 4, p(2) = 8

Step-by-step explanation:

refer to the attachment

Answer 2

Given polynomial is p(y)=2+y+2y^2-y^2

⇒p(0)=2+0+0+0

⇒p(0)=2

Replace y by 1, we get

p(1)=2+1+2(1)^2−(1^3

⇒p(1)=2+1+2−1

⇒p(1) =4

Replace y by 2, we get

p(2)=2+2+2(2)^2−(2)^3

⇒p(2)=2+2+8−8

⇒p(2)=4