Question

Find p(2 square rut 3,y p((x) =x2_2 square rut 3 x+1​

Answer 1

Answer:

p ( x ) = x² - 2√2x + 1

p ( 2√2 ) = ( 2√2 )² - ( 2√2 × 2√2 ) + 1

p ( 2√2 ) = ( 8 ) - ( 8 ) + 1

p ( 2√2 ) = 1