Question

find p(-3),p(5) and p(7) of polynomial p(x)=(x-5)(x+3)(x-7)​

Answer 1

Answer:

Step-by-step explanation:

P(x)=(x-5)(x+3)(x-7)

So p(-3)=(-3-5)(-3+3)(-3-7)=-8×0×(-10)=0

P(5)=(5-5)(5+3)(5-7)=0×8×(-2)=0

P(7)=(7-5)(7+3)(7-7)=2×10×0=0