Question

Find p^3-q^3..............
Plz

Answer 1

Kindly mark as brainliest if you are satisfied. Thanks!

Answer 2

Given that (p-q)=10/9 and pq=5/3.
${x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} + xy)$
=>
${x}^{3} - {y}^{3} = (x - y)( {(x - y)}^{2} + 3xy)$
So
${p}^{3} - {q}^{3} = (p - q)( {(p - q)}^{2} + 3pq)$
=>
${p}^{3} - {q}^{3} = ( \frac{10}{9} )(( \frac{10}{9})^{2} + 3( \frac{5}{3} )$
=> result of p^3-q^3 =10/9(100/81+5) =10/9(505/81) =
5050/729.. Hope it helps you...