Find p(4) , p(5) for : p(t) = 2 + t + 2t2 – t3
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I hope upper attachment will help you✌
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given p(t)=2+t+2t²-t³
let p(t)=4 then
2+4+2(4)²-4³
2+4+2(16)-64
6+32-64
38-64
= -26
let p(t)=5 then
2+5+2(5)²-5³
7+2(25)-125
7+50-125
= -68
we can do like this or change the equation in correct form means -t³+2t²+t+2 or t³-2t²-t-2 any this is correct only,we just need to substitute (keep) the given constant value in given variable place.hope this is helpful
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