find p(5) when p(x)=x^3+4
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15
Answer:
p(x) = x³ + 4
Then p(5) means we have to put value of x = 5
p(5) = 5³ + 4
= 125 + 4
= 129
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Answered by
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p(x)=x³+4
p(5)= 5³ +4 = 125 +4= 129
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