Question

find p for which (-3,9) (2,p) (4,-5) are collinear​

Answer 1

A(-3,9) B(2,p) C(4,-5)

area of triangle = 1/2{X1 (Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2)}

0 = 1/2 {-3(p+5)+2(-5-9)+4(-3-p)}

0 = -3p - 15 - 28 - 12 - 4p

0 = -7p -7

7p = -7

p = -7/7

p = -1

but area of triangle is 1 because the area can't be negative it will always positive

Answer 2

Answer:

Step-by-step explanation:

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