Question

Find P for which the equation Px^2 + 3x + 2 =0 has real roots.

Answer 1

Step-by-step explanation:

D=bxsquare-4ac

3square- 4.p2.2

9-16p

-7p

is less then zero it's has no real roots

Answer 2

Answer:

There are real roots so,

b2-4ac=0

on comparing ax2+bx+c=0

a=p,b=3&c=2

3*3-4*p*2=0

9=8p

P=9/8