Find P for which the equation Px^2 + 3x + 2 =0 has real roots.
Answers
Answered by
2
Step-by-step explanation:
D=bxsquare-4ac
3square- 4.p2.2
9-16p
-7p
is less then zero it's has no real roots
Answered by
1
Answer:
There are real roots so,
b2-4ac=0
on comparing ax2+bx+c=0
a=p,b=3&c=2
3*3-4*p*2=0
9=8p
P=9/8
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