Question

find p, if p (x-4) is a factor of 2x³+px²+27x-28​

Answer 1

Step-by-step explanation:

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Answer 2

x-4=0

x=4

$2 {x}^{3} + {px}^{2} + 27x - 28 = 0$

now put 4 in place of x

$2 \times {4}^{3} + p {4}^{2} + 27 \times 4 - 28 = 0$

$2 \times 64 + p \times 16 + 108 - 28 = 0$

$128 + 16p + 80 = 0$

$200 + 16p = 0$

$16p = - 200$

$p = - 200 \div 16$

$p = - 12.5$