Question

Find p if the lines 3x+4py+8=0 and 3py-9x+10=0 are perpendicular to each other

Answer 1

Step-by-step explanation:

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Answer 2

p = ± 3/2  if lines 3x+4py+8=0 and 3py-9x+10=0 are perpendicular to each other

Step-by-step explanation:

3x+4py+8=0 and 3py-9x+10=0 are perpendicular to each other

3x+4py+8=0

=> 4py =  -3x  - 8

=> y = -3x/4p   - 2/p

=> y = (-3/4p)x - 2/p

3py-9x+10=0

=> 3py = 9x - 10

=> y = 3x/p  - 10/3p

=> y = (3/p)x - 10/3p

Lines are perpendicular => multiplication of their slope = -1

(-3/4p)(3/p)  = - 1

=> 9/4 = p²

=> p = ± 3/2

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