Question

Find P, if the terms 3 P - 1, 3p + 5 and 5 p + 1 are in AP
Is it
A) 10
B)-10
c)1
D)-1​

Answer 1

Answer:

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☆ Given - A.p 3p - 1 , 3p + 5 and 5p + 1

☆ To find - Value of P

☆ Solution -

a = 3p - 1

d = a2 -a1

= (3p + 5) - (3p + 1 )

= 3p + 5 - 3p - 1

= 5 - 1

= 4

a3 = a4 + d

5p + 1 = 3p + 5 + 4

5p - 3p = 9 - 1

2p = 8

p = 8 /2

p = 4

Value of p is 4

Answer 2

Step-by-step explanation:

If the numbers a,b and c are in AP, then

b-a=c-b

⇒2b=a+c

The given three numbers (2p-1),(3p+1) and 11 are in AP.

Then,

2(3p+1)=(2p−1)+11

⇒6p+2=2p−1+11

⇒6p+2=2p+10

⇒6p−2p=10−2

⇒4p=8

⇒p=8/4

⇒p=2

So, the value of p is 2.

Then, the given numbers be

2×2−1,3×2+1,11

4−1,6+1,11

3,7,11

solution

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