Question

find p if x^3-3x^2+px-8 is divisible by x+2

Answer 1

Answer:

Let f(x) = x^3 + 4x^2 - px + 8

Since f(x) is exactly divisible by x - 2, we can say that x - 2 is a factor of f(x).

By the factor theorem,we know that since x - 2 is a factor of f(x), f(2) must be zero.

So, now:

f(2) = 0

2^3 + 4(2^2) - p(2) + 8 = 0

8 + 16 - 2p + 8 = 0

32 - 2p = 0

2p = 32

p = 32 / 2

p = 16

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Answer 2

Answer:

16

Step-by-step explanation:

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