Question

Find p in the quadratic equation so there are equal roots

Answer 1

✍️$\huge\bf\red{Answer}$✍️

px(x-3) + 9 = 0

px2-3px+9=0

a=p , b=-3p , c=9

b2-4ac= (-3p)2-4(p)(9)

=9p2-36p

for having equal roots

b2-4ac = 9p2-36p = 0

9p2-36p = 0

9p(p-4) = 0

9p=0 (or) p-4=0

p=0(rejected) or p=4

Answer 2

the value of P is 4

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