Question

find p(o),p(1) and p(2)for each of the following poynomials p(x)=x²-x+1​

Answer 1

Answer:

Step-by-step explanation:

p(x)=x²-x+1​

p(o)=1

p(1) =1

p(2)=3

Answer 2

Step-by-step explanation:

Given:-

p(x)=x²-x+1

To find:-

find p(o),p(1) and p(2)for each of the following polynomials p(x)=x²-x+1

Solution:-

put p(x)= 0

p(x)=x²-x+1

=> 0²-0+1

=> 0-0+1

=> 1

put p(x)= 1

p(x)=x²-x+1

=> 1²-1+1

=> 1-1+1

=> 1

put p(x)= 2

p(x)=x²-x+1

=> 2²-2+1

=> 4-2+1

=> 3

Therefore, by putting p(0)= 1, p(1)= 1, p(2)= 3