find p(o),p(1),p(2) for p(y)=y^2+y+1
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Answer:
Given p(0),p(1), and p(2) for p(y)
Step-by-step explanation:
i)let p(y) be p(0)
then,p(0)= y×2+y+1
p(0) = 0×2+0+1
= 0+0+1
=1
ii)let p(y) be p(1)
then, p(1)= 1×2+1+1
=2+1+1
=4
iii)let p(y)be p(2)
then,p(2)=2×2+2+1
=4+2+1
=7
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