Find P on this graph ?
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P =...
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Answer-: A(2, 0) is the zero of polynomial p(x) as it touched x axis at point (A)
this implies (alpha/zero of polynomial) =2
therefore p(x)=px^2 + 4x -4
p(2) =p(2)^2 +4×2-4
=4p +8-4 =0
p= -4/4= -1
HOPE IT WILL HELP
verification -: p(x) = -x^2 +4x -4
p(2) = -(2)^2 +4(2) -4
= -4 + 8 -4
= -8+8 =0 .
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