Find p(t)=4t³-t²+6 at t=1
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The polynomials p(t) = 4t3 - st2 + 7 and q(t) = t2 + st + 8 leave the same remainder when divided by (t - 1). find the value of s.
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p(t) = 4t³- t² + 6
t = 1
p(1) = 4(1)³- (1)² + 6
p(1) = 4 - 1 + 6
p(1) = 9
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