Question

Find p=?,where h=3 and b=4 class 10th pythagorus theorem

Answer 1

Answer:  Perpendicular(p) of the right-angled triangle= $\sqrt{-7}$

Step-by-step explanation:

Hypotenuse = 3

Base = 4

Finding perpendicular using pythagoras theorem :

$p^{2} + B^{2} = H^{2}\\P^{2} + 4^{2} = 3^{2}\\P^{2} + 16 = 9\\P^{2} = 9-16\\P^{2} = -7\\P = \sqrt{-7}$