find p where x=2,y=3 in the equation, (p+1)x+(2p+3)y-1=0
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Answered by
1
HEY DEAR!
X=2, Y=3
EQUATING,
(P+1)*2+(2P+3)*3-1=0
2P+2+(2P+3)*2=0
2P+2+4P+6=0
6P+8=0
6P=0-8
6P=-8
P= -8/6= -4/3
HOPE THIS HELPS
:)
adithya3112:
This is wrong
Answered by
2
(p+1)2+(2p+3)3-1 = 0
2p+2+6p+9-1 = 0
8p+10=0
8p= -10
P = -10/8
All the best
2p+2+6p+9-1 = 0
8p+10=0
8p= -10
P = -10/8
All the best
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