Question

find p which quadratic equation (p+1)x^2-6(p+1)x+3(p+q)=0 has equal roots find the roots of the equation

Answer 1

(p+1)x2−6(p+1)x+3(p+q)=0

Equal roots means, b2=4ac ( in quadratic ax2+bx+c=0 )

Hence root is x=−b2a

Applying to above,

Root is x=6(p+1)2(p+1)=3

And to find p, we use b2=4ac

36(p+1)2=4∗(p+1)∗3(p+q)

3(p+1)=p+q

2p=q−3

p=q−32

answered Oct 17, 2016 by pady_1

The value of p=3 q=9